What is the tangent of x=ln(xy),\at x=1 ?

The tangent of x=ln(xy),\at x=1 is y=e

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tangent of x=ln(xy),\at x=1

tangent of

x = ln (x y), at x = 1

y = e

Solution steps

Find the tangent point:

(1, e)

Find the slope of

x = ln (x y) : \frac{d y}{d x} = \frac{e ^{x} x - e ^{x}}{x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 0

Find the line with slope m=

0

and passing through

(1, e) : y = e

y = e

2 x + 1

\int \frac{2}{cos ^{2} ( x )} d x

y^{^{''}} + y^{^{'}} - 6 y = 0, y (0) = 5, y^{^{'}} (0) = 2

\int 5 x^{2} + 3 x + 2 d x

\int_{0}^{5} (1 + 2 x^{3}) d x

What is the tangent of x=ln(xy),\at x=1 ?
The tangent of x=ln(xy),\at x=1 is y=e