What is the derivative of-2x^2+x-1 ?

The derivative of-2x^2+x-1 is -4x+1

What is the first derivative of-2x^2+x-1 ?

The first derivative of-2x^2+x-1 is -4x+1

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\frac{d}{d x} (- 2 x^{2} + x - 1)

- 4 x + 1

Solution steps

\frac{d}{d x} (- 2 x^{2} + x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 x^{2}) + \frac{d x}{d x} - \frac{d}{d x} (1)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= - 4 x + 1 - 0

Simplify

= - 4 x + 1

x^{^{''}} + 3 x^{^{'}} + 2 x = 1

y^{^{'}} = \frac{1}{x} y - \frac{x ^{2}}{3} y^{4}, y (1) = 1

f (x) = (9 x + 3)^{3}

cos (sin (tan (π x)))

\frac{d ^{3} y}{d x ^{3}} + 4 \frac{d y}{d x} = 0

What is the derivative of-2x^2+x-1 ?
The derivative of-2x^2+x-1 is -4x+1
What is the first derivative of-2x^2+x-1 ?
The first derivative of-2x^2+x-1 is -4x+1