What is the solution for (d^3y)/(dx^3)+4(dy)/(dx)=0 ?

The solution for (d^3y)/(dx^3)+4(dy)/(dx)=0 is y=c_{1}+c_{2}cos(2x)+c_{3}sin(2x)

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(d^3y)/(dx^3)+4(dy)/(dx)=0

\frac{d ^{3} y}{d x ^{3}} + 4 \frac{d y}{d x} = 0

y = c_{1} + c_{2} cos (2 x) + c_{3} sin (2 x)

Solution steps

\frac{d ^{3} y}{d x ^{3}} + 4 \frac{d y}{d x} = 0

Solve linear ODE:

y = c_{1} + c_{2} cos (2 x) + c_{3} sin (2 x)

y = c_{1} + c_{2} cos (2 x) + c_{3} sin (2 x)

\frac{d y}{d x} = x + 2 y, y (0) = 4

\int_{0}^{8} x^{2} e^{- 3 x} d x

\int (\frac{8 x ^{4} - 4 x ^{3} - 7 x}{x}) d x

y \frac{d y}{d x} = e^{x}

\frac{\partial}{\partial x} (cos (x^{2}) \cdot sin (z \cdot y))

What is the solution for (d^3y)/(dx^3)+4(dy)/(dx)=0 ?
The solution for (d^3y)/(dx^3)+4(dy)/(dx)=0 is y=c_{1}+c_{2}cos(2x)+c_{3}sin(2x)