What is (\partial)/(\partial x)(e^{-3x^2-2y^2}) ?

The answer to (\partial)/(\partial x)(e^{-3x^2-2y^2}) is -6e^{-3x^2-2y^2}x

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(\partial)/(\partial x)(e^{-3x^2-2y^2})

\frac{\partial}{\partial x} (e^{- 3 x^{2} - 2 y^{2}})

- 6 e^{- 3 x^{2} - 2 y^{2}} x

Solution steps

\frac{\partial}{\partial x} (e^{- 3 x^{2} - 2 y^{2}})

Treat

y

as a constant

Apply the chain rule:

e^{- 3 x^{2} - 2 y^{2}} \frac{\partial}{\partial x} (- 3 x^{2} - 2 y^{2})

= e^{- 3 x^{2} - 2 y^{2}} \frac{\partial}{\partial x} (- 3 x^{2} - 2 y^{2})

\frac{\partial}{\partial x} (- 3 x^{2} - 2 y^{2}) = - 6 x

= e^{- 3 x^{2} - 2 y^{2}} (- 6 x)

Simplify

= - 6 e^{- 3 x^{2} - 2 y^{2}} x

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\int cos (x) sin (3 x) - 4 sin (x) d x

\frac{( x + 11 )}{( x - 11 )}

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What is (\partial)/(\partial x)(e^{-3x^2-2y^2}) ?
The answer to (\partial)/(\partial x)(e^{-3x^2-2y^2}) is -6e^{-3x^2-2y^2}x