What is the derivative of f(x)=((x^2)/(8-6x)) ?

The derivative of f(x)=((x^2)/(8-6x)) is (x(-3x+8))/(2(3x-4)^2)

What is the first derivative of f(x)=((x^2)/(8-6x)) ?

The first derivative of f(x)=((x^2)/(8-6x)) is (x(-3x+8))/(2(3x-4)^2)

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derivative of

f (x) = (\frac{x ^{2}}{8 - 6 x})

\frac{x ( - 3 x + 8 )}{2 ( 3 x - 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2}}{8 - 6 x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} ) ( 8 - 6 x ) - \frac{d}{d x} ( 8 - 6 x ) x ^{2}}{( 8 - 6 x ) ^{2}}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (8 - 6 x) = - 6

= \frac{2 x ( 8 - 6 x ) - ( - 6 ) x ^{2}}{( 8 - 6 x ) ^{2}}

Simplify

\frac{2 x ( 8 - 6 x ) - ( - 6 ) x ^{2}}{( 8 - 6 x ) ^{2}} : \frac{x ( - 3 x + 8 )}{2 ( 3 x - 4 ) ^{2}}

= \frac{x ( - 3 x + 8 )}{2 ( 3 x - 4 ) ^{2}}

x \to 5 lim (4 x - 20)

\frac{d}{d x} (3 x^{6} + 9 x - 3)

\int_{1}^{5} \frac{1}{x} d x

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\frac{d}{d x} (ln (x^{2} + 2 x + 5))

What is the derivative of f(x)=((x^2)/(8-6x)) ?
The derivative of f(x)=((x^2)/(8-6x)) is (x(-3x+8))/(2(3x-4)^2)
What is the first derivative of f(x)=((x^2)/(8-6x)) ?
The first derivative of f(x)=((x^2)/(8-6x)) is (x(-3x+8))/(2(3x-4)^2)