What is the limit as x approaches-1 of x^5+4x^2+x ?

The limit as x approaches-1 of x^5+4x^2+x is 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches-1 of x^5+4x^2+x

x \to - 1 lim (x^{5} + 4 x^{2} + x)

2

Solution steps

x \to - 1 lim (x^{5} + 4 x^{2} + x)

Plug in the value

x = - 1

= (- 1)^{5} + 4 (- 1)^{2} - 1

Simplify

(- 1)^{5} + 4 (- 1)^{2} - 1 : 2

= 2

\frac{d}{d x} (x^{2} - 2 x y)

\frac{d}{d x} (\frac{k}{x})

x \to 3 lim (\frac{∣ x - 3 ∣}{x - 3})

\frac{d y}{d x} = cot (x)

f (x) = \frac{8}{3} x^{3} - 16 x^{2} + 24 x + 4

What is the limit as x approaches-1 of x^5+4x^2+x ?
The limit as x approaches-1 of x^5+4x^2+x is 2