What is the solution for (dy)/(dx)=2y-xy^2 ?

The solution for (dy)/(dx)=2y-xy^2 is y=(4e^{2x})/(2e^{2x)x-e^{2x}+c_{1}}

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(dy)/(dx)=2y-xy^2

\frac{d y}{d x} = 2 y - x y^{2}

y = \frac{4 e ^{2 x}}{2 e ^{2 x} x - e ^{2 x} + c _{1}}

Solution steps

\frac{d y}{d x} = 2 y - x y^{2}

Solve Bernoulli ODE:

y = \frac{4 e ^{2 x}}{2 e ^{2 x} x - e ^{2 x} + c _{1}}

y = \frac{4 e ^{2 x}}{2 e ^{2 x} x - e ^{2 x} + c _{1}}

\frac{d}{d x} ((2 x - 1) sin (x - 2))

y = \frac{5}{ln ( x )}

f^{^{''}} (x) = e^{x}

\int x^{3} e^{5 x} d x

1 - 2 e^{- 2 t} + e^{- 4 t}

What is the solution for (dy)/(dx)=2y-xy^2 ?
The solution for (dy)/(dx)=2y-xy^2 is y=(4e^{2x})/(2e^{2x)x-e^{2x}+c_{1}}