What is the d/(d{x)}({x}^2{y}^2{z}^2) ?

The d/(d{x)}({x}^2{y}^2{z}^2) is 2{y}^2{z}^2{x}

What is the first d/(d{x)}({x}^2{y}^2{z}^2) ?

The first d/(d{x)}({x}^2{y}^2{z}^2) is 2{y}^2{z}^2{x}

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\frac{d}{d x} (x^{2} y^{2} z^{2})

2 y^{2} z^{2} x

Solution steps

\frac{d}{d x} (x^{2} y^{2} z^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y^{2} z^{2} \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= y^{2} z^{2} \cdot 2 x^{2 - 1}

Simplify

= 2 y^{2} z^{2} x

\int \frac{1}{25 + 4 x ^{2}} d x

\int \frac{sin ( x ) - 4}{cos ( x )} d x

\int \frac{sin ^{2} ( x )}{x} d x

\int e^{- 2 y} d y

\frac{d}{d x} (900 x - \frac{1}{3} x^{3} + 2500)

What is the d/(d{x)}({x}^2{y}^2{z}^2) ?
The d/(d{x)}({x}^2{y}^2{z}^2) is 2{y}^2{z}^2{x}
What is the first d/(d{x)}({x}^2{y}^2{z}^2) ?
The first d/(d{x)}({x}^2{y}^2{z}^2) is 2{y}^2{z}^2{x}