What is the integral from-infinity to 0 of (4-3x)e^x ?

The integral from-infinity to 0 of (4-3x)e^x is 7

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integral from-infinity to 0 of (4-3x)e^x

\int_{- \infty}^{0} (4 - 3 x) e^{x} d x

7

Solution steps

\int_{- \infty}^{0} (4 - 3 x) e^{x} d x

Compute the indefinite integral:

\int (4 - 3 x) e^{x} d x = - 3 e^{x} x + 7 e^{x} + C

Compute the boundaries:

\int_{- \infty}^{0} (4 - 3 x) e^{x} d x = 7 - 0

= 7 - 0

Simplify

= 7

f (x) = (2 x + 1) (3 x^{2} + 2)

\int \frac{e ^{x}}{e ^{2 x} - 1} d x

\int_{0}^{4} \frac{3}{x ^{2}} d x

y = 10 - x^{2}, y = 4

\frac{d ^{2}}{d x ^{2}} (5 e^{x})

What is the integral from-infinity to 0 of (4-3x)e^x ?
The integral from-infinity to 0 of (4-3x)e^x is 7