What is the derivative of y=8cos(x) ?

The derivative of y=8cos(x) is -8sin(x)

What is the first derivative of y=8cos(x) ?

The first derivative of y=8cos(x) is -8sin(x)

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derivative of

y = 8 cos (x)

- 8 sin (x)

Solution steps

\frac{d}{d x} (8 cos (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (cos (x))

Apply the common derivative:

\frac{d}{d x} (cos (x)) = - sin (x)

= 8 (- sin (x))

Simplify

= - 8 sin (x)

cos^{2} (x) sin (x) y^{^{'}} + (cos^{3} (x)) y = 1

(4 x^{2} + 5) (3 x - 2)

x \to 4 lim (\frac{a x ^{3}}{x - 4})

\frac{d y}{d x} = (x y)^{\frac{1}{3}}, y (2) = 1

\frac{d}{d x} (7 x e^{- 9 x})

What is the derivative of y=8cos(x) ?
The derivative of y=8cos(x) is -8sin(x)
What is the first derivative of y=8cos(x) ?
The first derivative of y=8cos(x) is -8sin(x)