What is the integral of \sqrt[7]{x^2} ?

The integral of \sqrt[7]{x^2} is 7/9 x^{9/7}+C

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integral of \sqrt[7]{x^2}

\int 7 x^{2} d x

\frac{7}{9} x^{\frac{9}{7}} + C

Solution steps

\int 7 x^{2} d x

7 x^{2} = x^{\frac{2}{7}},

assuming

x \geq 0

= \int x^{\frac{2}{7}} d x

Apply the Power Rule

: \frac{7}{9} x^{\frac{9}{7}}

= \frac{7}{9} x^{\frac{9}{7}}

Add a constant to the solution

= \frac{7}{9} x^{\frac{9}{7}} + C

\frac{d}{d x} (x^{2} (5 x - 1)^{3})

f (x) = (x^{2} + 1) (x^{3} + 1)

\frac{\partial}{\partial z} (x + e^{z} + y)

x y^{^{'}} + ln (x) y = 0

f (x) = 2 x^{3} + 3 x^{2} - 12 x + 2

What is the integral of \sqrt[7]{x^2} ?
The integral of \sqrt[7]{x^2} is 7/9 x^{9/7}+C