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Popular >

xy^'+ln(x)y=0

Solution

x y^{^{'}} + ln (x) y = 0

Solution

y = e^{- \frac{l n ^{2} ( x )}{2} + c_{1}}

Solution steps

x y^{'} (x) + ln (x) y = 0

Solve separable ODE:

y = e^{- \frac{l n ^{2} ( x )}{2} + c_{1}}

y = e^{- \frac{l n ^{2} ( x )}{2} + c_{1}}

Graph

Popular Examples

derivative of f(x)=2x^3+3x^2-12x+2 derivative of

f (x) = 2 x^{3} + 3 x^{2} - 12 x + 2

limit as x approaches 4-of (x+5)/(x-4)

x \to 4 - lim (\frac{x + 5}{x - 4})

tangent of y=x^2+2x-1,(1,2)tangent of

y = x^{2} + 2 x - 1, (1, 2)

area sqrt(x),y=2,x=0 area

x, y = 2, x = 0

(\partial)/(\partial x)(sin(x)+cos(y))

\frac{\partial}{\partial x} (sin (x) + cos (y))

Frequently Asked Questions (FAQ)

What is the solution for xy^'+ln(x)y=0 ?
The solution for xy^'+ln(x)y=0 is y=e^{-(ln^2(x))/2+c_{1}}