What is the derivative of f(x)=8x^5-8cos(x) ?

The derivative of f(x)=8x^5-8cos(x) is 40x^4+8sin(x)

What is the first derivative of f(x)=8x^5-8cos(x) ?

The first derivative of f(x)=8x^5-8cos(x) is 40x^4+8sin(x)

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derivative of

f (x) = 8 x^{5} - 8 cos (x)

40 x^{4} + 8 sin (x)

Solution steps

\frac{d}{d x} (8 x^{5} - 8 cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x^{5}) - \frac{d}{d x} (8 cos (x))

\frac{d}{d x} (8 x^{5}) = 40 x^{4}

\frac{d}{d x} (8 cos (x)) = - 8 sin (x)

= 40 x^{4} - (- 8 sin (x))

Simplify

= 40 x^{4} + 8 sin (x)

\frac{d}{d x} (x^{x c o s (x)})

x^{2} + 4 ln^{2} (x)

ln (x^{2})

\frac{- 3 x ^{5} - x ^{4} - x ^{3} + 4 x ^{2}}{x ^{2}}

x \frac{d y}{d x} = 4 y

What is the derivative of f(x)=8x^5-8cos(x) ?
The derivative of f(x)=8x^5-8cos(x) is 40x^4+8sin(x)
What is the first derivative of f(x)=8x^5-8cos(x) ?
The first derivative of f(x)=8x^5-8cos(x) is 40x^4+8sin(x)