What is the derivative of x^2+4ln^2(x) ?

The derivative of x^2+4ln^2(x) is 2x+(8ln(x))/x

What is the first derivative of x^2+4ln^2(x) ?

The first derivative of x^2+4ln^2(x) is 2x+(8ln(x))/x

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derivative of

x^{2} + 4 ln^{2} (x)

2 x + \frac{8 ln ( x )}{x}

Solution steps

\frac{d}{d x} (x^{2} + 4 ln^{2} (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4 ln^{2} (x))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 ln^{2} (x)) = \frac{8 ln ( x )}{x}

= 2 x + \frac{8 ln ( x )}{x}

ln (x^{2})

\frac{- 3 x ^{5} - x ^{4} - x ^{3} + 4 x ^{2}}{x ^{2}}

x \frac{d y}{d x} = 4 y

y = x^{3}, x = - 1, x = 2, y = 0

\frac{\partial}{\partial x} (\frac{3}{4} (2 - 3 x)^{\frac{4}{3}})

What is the derivative of x^2+4ln^2(x) ?
The derivative of x^2+4ln^2(x) is 2x+(8ln(x))/x
What is the first derivative of x^2+4ln^2(x) ?
The first derivative of x^2+4ln^2(x) is 2x+(8ln(x))/x