What is area y=x^3,x=-1,x=2,y=0 ?

The answer to area y=x^3,x=-1,x=2,y=0 is 17/4

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area y=x^3,x=-1,x=2,y=0

area

y = x^{3}, x = - 1, x = 2, y = 0

\frac{17}{4}

Decimal

4.25

Solution steps

Apply the area formula:

\int_{- 1}^{2} x^{3} d x

Solve

\int_{- 1}^{2} x^{3} d x : \frac{17}{4}

The area is:

= \frac{17}{4}

\frac{\partial}{\partial x} (\frac{3}{4} (2 - 3 x)^{\frac{4}{3}})

x \to 2 lim (2 x (x^{2} - 3))

\frac{d y}{d x} = \frac{e ^{x + y}}{y - 1}

y = 3 x^{2}, y = x^{4} - x^{2}

f (x) = 3 + 4 x^{2} - 2 x^{3}