What is the solution for (dy)/(dx)=(e^{x+y})/(y-1) ?

The solution for (dy)/(dx)=(e^{x+y})/(y-1) is y=-\W(e^x+c_{1})

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(dy)/(dx)=(e^{x+y})/(y-1)

\frac{d y}{d x} = \frac{e ^{x + y}}{y - 1}

y = - W (e^{x} + c_{1})

Solution steps

\frac{d y}{d x} = \frac{e ^{x + y}}{y - 1}

Solve separable ODE:

y = - W (e^{x} + c_{1})

y = - W (e^{x} + c_{1})

y = 3 x^{2}, y = x^{4} - x^{2}

f (x) = 3 + 4 x^{2} - 2 x^{3}

\int \frac{1}{x ^{2} - y} d x

f (x) = tan (x)

- \frac{1}{2} cos^{2} (x)

What is the solution for (dy)/(dx)=(e^{x+y})/(y-1) ?
The solution for (dy)/(dx)=(e^{x+y})/(y-1) is y=-\W(e^x+c_{1})