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Popular >

area y=3x^2,y=x^4-x^2

Solution

area

y = 3 x^{2}, y = x^{4} - x^{2}

Solution

\frac{128}{15}

+1

Solution steps

Apply the area formula:

\int_{- 2}^{2} 3 x^{2} - (x^{4} - x^{2}) d x

Solve

\int_{- 2}^{2} 3 x^{2} - (x^{4} - x^{2}) d x : \frac{128}{15}

The area is:

= \frac{128}{15}

Popular Examples

tangent of f(x)=3+4x^2-2x^3 tangent of

f (x) = 3 + 4 x^{2} - 2 x^{3}

integral of 1/(x^2-y)

\int \frac{1}{x ^{2} - y} d x

f(x)=tan(sqrt(x))

f (x) = tan (x)

derivative of-1/2 cos^2(x)derivative of

- \frac{1}{2} cos^{2} (x)

tangent of y=x^2-3x-4,(2,-6)tangent of

y = x^{2} - 3 x - 4, (2, - 6)

Frequently Asked Questions (FAQ)

What is area y=3x^2,y=x^4-x^2 ?
The answer to area y=3x^2,y=x^4-x^2 is 128/15