What is the tangent of y=x^2-3x-4,(2,-6) ?

The tangent of y=x^2-3x-4,(2,-6) is y=x-8

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tangent of y=x^2-3x-4,(2,-6)

tangent of

y = x^{2} - 3 x - 4, (2, - 6)

y = x - 8

Solution steps

Find the slope of

y = x^{2} - 3 x - 4 : \frac{d y}{d x} = 2 x - 3

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 1

Find the line with slope m=

1

and passing through

(2, - 6) : y = x - 8

y = x - 8

\int_{0}^{2} 5^{x} d x

\int arccot (x) d x

y^{^{'}} + 2 y = t e^{- 2 t}

x^{2} y^{^{''}} + 2 x y^{^{'}} + 100.25 y = 0

\frac{d}{d x} (\frac{150 x}{x + 8})

What is the tangent of y=x^2-3x-4,(2,-6) ?
The tangent of y=x^2-3x-4,(2,-6) is y=x-8