What is the integral from 0 to 2 of 5^x ?

The integral from 0 to 2 of 5^x is (24)/(ln(5))

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integral from 0 to 2 of 5^x

\int_{0}^{2} 5^{x} d x

\frac{24}{ln ( 5 )}

Decimal

14.91203 \dots

Solution steps

\int_{0}^{2} 5^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{5 ^{x}}{ln ( 5 )}]_{0}^{2}

Compute the boundaries:

\frac{24}{ln ( 5 )}

= \frac{24}{ln ( 5 )}

\int arccot (x) d x

y^{^{'}} + 2 y = t e^{- 2 t}

x^{2} y^{^{''}} + 2 x y^{^{'}} + 100.25 y = 0

\frac{d}{d x} (\frac{150 x}{x + 8})

f (x) = (ln (x))^{2}

What is the integral from 0 to 2 of 5^x ?
The integral from 0 to 2 of 5^x is (24)/(ln(5))