What is the limit as x approaches 1 of x^{9/(1-x)} ?

The limit as x approaches 1 of x^{9/(1-x)} is 1/(e^9)

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limit as x approaches 1 of x^{9/(1-x)}

x \to 1 lim (x^{\frac{9}{1 - x}})

\frac{1}{e ^{9}}

Decimal

0.00012 \dots

Solution steps

x \to 1 lim (x^{\frac{9}{1 - x}})

Apply exponent rules

= x \to 1 lim (e^{\frac{9}{1 - x} l n (x)})

Apply the Limit Chain Rule:

\frac{1}{e ^{9}}

= \frac{1}{e ^{9}}

- 6 sin (t)

\int \frac{1}{v ln ( v ) - v} d v

ln (e^{x} + x)

x + 6

\frac{d}{d x} (\frac{x ^{2} - 3 x - 4}{x})

What is the limit as x approaches 1 of x^{9/(1-x)} ?
The limit as x approaches 1 of x^{9/(1-x)} is 1/(e^9)