What is the derivative of y=t^3-2t+4 ?

The derivative of y=t^3-2t+4 is 3t^2-2

What is the first derivative of y=t^3-2t+4 ?

The first derivative of y=t^3-2t+4 is 3t^2-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = t^{3} - 2 t + 4

3 t^{2} - 2

Solution steps

\frac{d}{d t} (t^{3} - 2 t + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (t^{3}) - \frac{d}{d t} (2 t) + \frac{d}{d t} (4)

\frac{d}{d t} (t^{3}) = 3 t^{2}

\frac{d}{d t} (2 t) = 2

\frac{d}{d t} (4) = 0

= 3 t^{2} - 2 + 0

Simplify

= 3 t^{2} - 2

\frac{x ^{3}}{3} + \frac{x ^{2}}{2} - 6 x + 5

x \to 0 lim (\frac{( 2 + x ) ^{2} + 4}{x})

\frac{1}{x ( 5 + ln ( x ) )}

\frac{d y}{d x} = 2 e^{(x - y)}

\frac{d}{d x} (a e^{- x} + b x e^{- x})

What is the derivative of y=t^3-2t+4 ?
The derivative of y=t^3-2t+4 is 3t^2-2
What is the first derivative of y=t^3-2t+4 ?
The first derivative of y=t^3-2t+4 is 3t^2-2