What is the derivative of sqrt(7+x) ?

The derivative of sqrt(7+x) is 1/(2sqrt(7+x))

What is the first derivative of sqrt(7+x) ?

The first derivative of sqrt(7+x) is 1/(2sqrt(7+x))

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\frac{d}{d x} (7 + x)

\frac{1}{2 7 + x}

Solution steps

\frac{d}{d x} (7 + x)

Apply the chain rule:

\frac{1}{2 7 + x} \frac{d}{d x} (7 + x)

= \frac{1}{2 7 + x} \frac{d}{d x} (7 + x)

\frac{d}{d x} (7 + x) = 1

= \frac{1}{2 7 + x} \cdot 1

Simplify

= \frac{1}{2 7 + x}

x \to \infty lim (\frac{0}{+ x})

y^{^{''}} + 2 y^{^{'}} - 3 y = e^{- x}, y (0) = 0

f (x) = \frac{4}{1 - 6 x}

n = 1 \sum \infty \frac{4}{3 ^{n - 1}}

x \to 2 lim (lo g_{10 x} (x))

What is the derivative of sqrt(7+x) ?
The derivative of sqrt(7+x) is 1/(2sqrt(7+x))
What is the first derivative of sqrt(7+x) ?
The first derivative of sqrt(7+x) is 1/(2sqrt(7+x))