What is the derivative of ln(2x) ?

The derivative of ln(2x) is 1/x

What is the first derivative of ln(2x) ?

The first derivative of ln(2x) is 1/x

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derivative of

ln (2 x)

\frac{1}{x}

Solution steps

\frac{d}{d x} (ln (2 x))

Apply the chain rule:

\frac{1}{2 x} \frac{d}{d x} (2 x)

= \frac{1}{2 x} \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= \frac{1}{2 x} \cdot 2

Simplify

\frac{1}{2 x} \cdot 2 : \frac{1}{x}

= \frac{1}{x}

n = 0 \sum \infty \frac{1}{n ^{4} + 6}

f (x) = x, at x = 5

f^{^{''}} (t) - f (t) = - 8 t, f (3) = - 8

f (x) = \frac{2 x - 1}{4 x + 8}

\frac{1}{1 + x ^{3}}