What is the sum from n=0 to infinity of 1/(n^4+6) ?

The sum from n=0 to infinity of 1/(n^4+6) is converges

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sum from n=0 to infinity of 1/(n^4+6)

n = 0 \sum \infty \frac{1}{n ^{4} + 6}

converges

Solution steps

n = 0 \sum \infty \frac{1}{n ^{4} + 6}

Apply Series Comparison Test:

converges

= converges

f (x) = x, at x = 5

f^{^{''}} (t) - f (t) = - 8 t, f (3) = - 8

f (x) = \frac{2 x - 1}{4 x + 8}

\frac{1}{1 + x ^{3}}

\frac{\partial}{\partial y} (4 y - 2 x)

What is the sum from n=0 to infinity of 1/(n^4+6) ?
The sum from n=0 to infinity of 1/(n^4+6) is converges