What is the sum from n=1 to infinity of 1/(n^{0.08)} ?

The sum from n=1 to infinity of 1/(n^{0.08)} is diverges

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sum from n=1 to infinity of 1/(n^{0.08)}

n = 1 \sum \infty \frac{1}{n ^{0.08}}

diverges

Solution steps

n = 1 \sum \infty \frac{1}{n ^{0.08}}

Apply p-Series Test:

diverges

= diverges

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What is the sum from n=1 to infinity of 1/(n^{0.08)} ?
The sum from n=1 to infinity of 1/(n^{0.08)} is diverges