What is the derivative of cy^{-8} ?

The derivative of cy^{-8} is -(8c)/(y^9)

What is the first derivative of cy^{-8} ?

The first derivative of cy^{-8} is -(8c)/(y^9)

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derivative of

c y^{- 8}

- \frac{8 c}{y ^{9}}

Solution steps

\frac{d}{d y} (c y^{- 8})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= c \frac{d}{d y} (y^{- 8})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= c (- 8 y^{- 8 - 1})

Simplify

c (- 8 y^{- 8 - 1}) : - \frac{8 c}{y ^{9}}

= - \frac{8 c}{y ^{9}}

\frac{d}{d x} (2 x^{0.5})

y = e^{\frac{7}{9} x}

\int 2 sin^{3} (x co) s^{7} x

f (x) = \frac{9}{x}, at x = 5

\frac{d}{d x} (\frac{2 x - 3}{x ^{2}})

What is the derivative of cy^{-8} ?
The derivative of cy^{-8} is -(8c)/(y^9)
What is the first derivative of cy^{-8} ?
The first derivative of cy^{-8} is -(8c)/(y^9)