What is (\partial)/(\partial y)(2x+4y) ?

The answer to (\partial)/(\partial y)(2x+4y) is 4

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(\partial)/(\partial y)(2x+4y)

\frac{\partial}{\partial y} (2 x + 4 y)

4

Solution steps

\frac{\partial}{\partial y} (2 x + 4 y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x) + \frac{\partial}{\partial y} (4 y)

\frac{\partial}{\partial y} (2 x) = 0

\frac{\partial}{\partial y} (4 y) = 4

= 0 + 4

Simplify

= 4

f (x) = 2 x - 1

x \to \infty lim (e^{- x} - ln (x))

\int \frac{8 x ^{2} + x + 73}{( x + 1 ) ( x ^{2} + 9 )} d x

7 (x^{3} - x)^{4}

\frac{d}{d x} (\frac{3 x - 8}{x ^{2} - 1})

What is (\partial)/(\partial y)(2x+4y) ?
The answer to (\partial)/(\partial y)(2x+4y) is 4