What is the derivative of y= 1/(y^2) ?

The derivative of y= 1/(y^2) is -2/(y^3)

What is the first derivative of y= 1/(y^2) ?

The first derivative of y= 1/(y^2) is -2/(y^3)

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derivative of

y = \frac{1}{y ^{2}}

- \frac{2}{y ^{3}}

Solution steps

\frac{d}{d y} (\frac{1}{y ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d y} (y^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 2 y^{- 2 - 1}

Simplify

- 2 y^{- 2 - 1} : - \frac{2}{y ^{3}}

= - \frac{2}{y ^{3}}

\frac{\partial}{\partial x} (r sin (θ))

\int_{- 6}^{6} \frac{( 36 - x ^{2} )}{2} d x

\int 7 r e^{\frac{r}{4}} d r

\frac{d}{d x} (\frac{1}{( x - 1 ) ^{3}})

f (x) = x^{2} - 4, y = 0, x = - 4, x = 3

What is the derivative of y= 1/(y^2) ?
The derivative of y= 1/(y^2) is -2/(y^3)
What is the first derivative of y= 1/(y^2) ?
The first derivative of y= 1/(y^2) is -2/(y^3)