What is area f(x)=x^2-4,y=0,x=-4,x=3 ?

The answer to area f(x)=x^2-4,y=0,x=-4,x=3 is 71/3

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area f(x)=x^2-4,y=0,x=-4,x=3

area

f (x) = x^{2} - 4, y = 0, x = - 4, x = 3

\frac{71}{3}

Decimal

23.66666 \dots

Solution steps

Apply the area formula:

\int_{- 4}^{3} x^{2} - 4 d x

Solve

\int_{- 4}^{3} x^{2} - 4 d x : \frac{71}{3}

The area is:

= \frac{71}{3}

y = x^{2} - 6, (4, 10)

\frac{d}{d x} (x x^{\frac{1}{2}})

5 x^{2} + x y + 5 y^{2} = 11, (1, 1)

\int - 4 + 9 s d s

\frac{d}{d x} (sin^{5} (x^{2} + 1)^{7})

What is area f(x)=x^2-4,y=0,x=-4,x=3 ?
The answer to area f(x)=x^2-4,y=0,x=-4,x=3 is 71/3