What is (d^2)/(dx^2)((x^2-6x)/(x+1)) ?

The answer to (d^2)/(dx^2)((x^2-6x)/(x+1)) is (14)/((x+1)^3)

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(d^2)/(dx^2)((x^2-6x)/(x+1))

\frac{d ^{2}}{d x ^{2}} (\frac{x ^{2} - 6 x}{x + 1})

\frac{14}{( x + 1 ) ^{3}}

Solution steps

\frac{d ^{2}}{d x ^{2}} (\frac{x ^{2} - 6 x}{x + 1})

\frac{d}{d x} (\frac{x ^{2} - 6 x}{x + 1}) = \frac{x ^{2} + 2 x - 6}{( x + 1 ) ^{2}}

= \frac{d}{d x} (\frac{x ^{2} + 2 x - 6}{( x + 1 ) ^{2}})

\frac{d}{d x} (\frac{x ^{2} + 2 x - 6}{( x + 1 ) ^{2}}) = \frac{14}{( x + 1 ) ^{3}}

= \frac{14}{( x + 1 ) ^{3}}

x \to 1 lim \frac{( x ^{\frac{5}{2}} - 2 x ^{\frac{3}{2}} + x ^{\frac{1}{2}} )}{x - 1}

f (x) = (a - 5 x) (a + 5 x)

\int 4 sec^{6} (t) d t

2 y^{^{''}} + 19 y^{^{'}} - 10 y = 0

x \to 0 + lim (\frac{x ^{2}}{6} - \frac{4}{x})

What is (d^2)/(dx^2)((x^2-6x)/(x+1)) ?
The answer to (d^2)/(dx^2)((x^2-6x)/(x+1)) is (14)/((x+1)^3)