What is the limit as x approaches 0+of (x^2)/6-4/x ?

The limit as x approaches 0+of (x^2)/6-4/x is -infinity

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limit as x approaches 0+of (x^2)/6-4/x

x \to 0 + lim (\frac{x ^{2}}{6} - \frac{4}{x})

- \infty

Solution steps

x \to 0 + lim (\frac{x ^{2}}{6} - \frac{4}{x})

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to 0 + lim (\frac{x ^{2}}{6}) - x \to 0 + lim (\frac{4}{x})

x \to 0 + lim (\frac{x ^{2}}{6}) = 0

x \to 0 + lim (\frac{4}{x}) = \infty

= 0 - \infty

Apply Infinity Property:

c - \infty = - \infty

= - \infty

\frac{\partial}{\partial y} (e^{2 x} cos (2 y))

y^{^{'}} = e^{x - 2 y}

x = - 2, x = 3, y = 2 x^{2} + 6, y = 0

x \to 0 + lim (\frac{x ^{2} + 1}{x})

x \to 2 lim (\frac{1}{x ^{2} - 9})

What is the limit as x approaches 0+of (x^2)/6-4/x ?
The limit as x approaches 0+of (x^2)/6-4/x is -infinity