What is the derivative of ye^y ?

The derivative of ye^y is e^y+e^yy

What is the first derivative of ye^y ?

The first derivative of ye^y is e^y+e^yy

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derivative of

y e^{y}

e^{y} + e^{y} y

Solution steps

\frac{d}{d y} (y e^{y})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = y, g = e^{y}

= \frac{d y}{d y} e^{y} + \frac{d}{d y} (e^{y}) y

\frac{d y}{d y} = 1

\frac{d}{d y} (e^{y}) = e^{y}

= 1 \cdot e^{y} + e^{y} y

Simplify

= e^{y} + e^{y} y

\int x cos (n) π x d x

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z \to - 2 lim (\frac{z ^{2} - 9}{z - 3})

\int (6 - x^{2})^{\frac{3}{2}} d x

n = 0 \sum \infty \frac{1}{2 - e ^{n}}