What is the derivative of f(x)=(3x)/(x^2-1) ?

The derivative of f(x)=(3x)/(x^2-1) is (3(-x^2-1))/((x^2-1)^2)

What is the first derivative of f(x)=(3x)/(x^2-1) ?

The first derivative of f(x)=(3x)/(x^2-1) is (3(-x^2-1))/((x^2-1)^2)

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derivative of

f (x) = \frac{3 x}{x ^{2} - 1}

\frac{3 ( - x ^{2} - 1 )}{( x ^{2} - 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{3 x}{x ^{2} - 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{x}{x ^{2} - 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 3 \cdot \frac{\frac{d x}{d x} ( x ^{2} - 1 ) - \frac{d}{d x} ( x ^{2} - 1 ) x}{( x ^{2} - 1 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x^{2} - 1) = 2 x

= 3 \cdot \frac{1 \cdot ( x ^{2} - 1 ) - 2 xx}{( x ^{2} - 1 ) ^{2}}

Simplify

3 \cdot \frac{1 \cdot ( x ^{2} - 1 ) - 2 xx}{( x ^{2} - 1 ) ^{2}} : \frac{3 ( - x ^{2} - 1 )}{( x ^{2} - 1 ) ^{2}}

= \frac{3 ( - x ^{2} - 1 )}{( x ^{2} - 1 ) ^{2}}

\int_{0}^{5} π (\frac{y ^{2}}{3})^{2} d y

\int (8 x - 12) (4 x^{2} - 12 x) d x

7 sin (x)

y = ln (\frac{x + 1}{x - 1})

\frac{d y}{d t} = 2 t y^{2} + 3 y^{2}

What is the derivative of f(x)=(3x)/(x^2-1) ?
The derivative of f(x)=(3x)/(x^2-1) is (3(-x^2-1))/((x^2-1)^2)
What is the first derivative of f(x)=(3x)/(x^2-1) ?
The first derivative of f(x)=(3x)/(x^2-1) is (3(-x^2-1))/((x^2-1)^2)