What is the solution for y^{''}+25y=cos(5t) ?

The solution for y^{''}+25y=cos(5t) is y=c_{1}cos(5t)+c_{2}sin(5t)+(tsin(5t))/(10)

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y^{''}+25y=cos(5t)

y^{^{''}} + 25 y = cos (5 t)

y = c_{1} cos (5 t) + c_{2} sin (5 t) + \frac{t sin ( 5 t )}{10}

Solution steps

y^{''} (t) + 25 y = cos (5 t)

Solve linear ODE:

y = c_{1} cos (5 t) + c_{2} sin (5 t) + \frac{t sin ( 5 t )}{10}

y = c_{1} cos (5 t) + c_{2} sin (5 t) + \frac{t sin ( 5 t )}{10}

Y = Y = ln (x - 3)

\int sin (2 x) \cdot e^{x} d x

\int_{0}^{\frac{1}{5}} 2 arcsin (5 y) d y

f (x) = sin (x) csc (x)

(sec (x) + tan (x)) (sec (x) - tan (x))

What is the solution for y^{''}+25y=cos(5t) ?
The solution for y^{''}+25y=cos(5t) is y=c_{1}cos(5t)+c_{2}sin(5t)+(tsin(5t))/(10)