What is derivative of Y=Y=ln(sqrt(x-3)) ?

The answer to derivative of Y=Y=ln(sqrt(x-3)) is (dY)/(dx)= 1/(2(x-3))

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derivative of Y=Y=ln(sqrt(x-3))

derivative of

Y = Y = ln (x - 3)

\frac{d Y}{d x} = \frac{1}{2 ( x - 3 )}

Solution steps

Y = Y = ln (x - 3)

Treat

Y

Y (x)

Differentiate both sides:

\frac{d Y}{d x} = \frac{1}{2 ( x - 3 )}

Isolate

\frac{d Y}{d x} : \frac{d Y}{d x} = \frac{1}{2 ( x - 3 )}

\frac{d Y}{d x} = \frac{1}{2 ( x - 3 )}

\int sin (2 x) \cdot e^{x} d x

\int arctan (x^{2}) d x

\int_{0}^{\frac{1}{5}} 2 arcsin (5 y) d y

f (x) = sin (x) csc (x)

(sec (x) + tan (x)) (sec (x) - tan (x))

What is derivative of Y=Y=ln(sqrt(x-3)) ?
The answer to derivative of Y=Y=ln(sqrt(x-3)) is (dY)/(dx)= 1/(2(x-3))