What is partialfraction (x^2)/(x^2-9) ?

The solution to partialfraction (x^2)/(x^2-9) is 1-3/(2(x+3))+3/(2(x-3))

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partialfraction (x^2)/(x^2-9)

partial fractions

\frac{x ^{2}}{x ^{2} - 9}

1 - \frac{3}{2 ( x + 3 )} + \frac{3}{2 ( x - 3 )}

Solution steps

\frac{x ^{2}}{x ^{2} - 9}

Long division

\frac{x ^{2}}{x ^{2} - 9} : 1 + \frac{9}{x ^{2} - 9}

= 1 + \frac{9}{x ^{2} - 9}

Continue partial fractions on remainder:

\frac{9}{x ^{2} - 9}

Take the partial fraction of

\frac{9}{x ^{2} - 9} : - \frac{3}{2 ( x + 3 )} + \frac{3}{2 ( x - 3 )}

1 - \frac{3}{2 ( x + 3 )} + \frac{3}{2 ( x - 3 )}

x \to 0 lim (\frac{( 3 e ^{x} - 3 )}{x})

\int + (x) d x

\int 4 tan^{4} (x se) c^{6} x d x

x \to - \infty lim ((1 + \frac{1}{x})^{2 x})

\frac{9}{x + 2}

What is partialfraction (x^2)/(x^2-9) ?
The solution to partialfraction (x^2)/(x^2-9) is 1-3/(2(x+3))+3/(2(x-3))