What is the derivative of 4x^3-26x^2+40x ?

The derivative of 4x^3-26x^2+40x is 12x^2-52x+40

What is the first derivative of 4x^3-26x^2+40x ?

The first derivative of 4x^3-26x^2+40x is 12x^2-52x+40

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\frac{d}{d x} (4 x^{3} - 26 x^{2} + 40 x)

12 x^{2} - 52 x + 40

Solution steps

\frac{d}{d x} (4 x^{3} - 26 x^{2} + 40 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{3}) - \frac{d}{d x} (26 x^{2}) + \frac{d}{d x} (40 x)

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (26 x^{2}) = 52 x

\frac{d}{d x} (40 x) = 40

= 12 x^{2} - 52 x + 40

y^{^{''}} + 5 y^{^{'}} + 4 y = - 19 t e^{5 t}

\frac{d}{d x} (x^{3} - 3 x^{2} + 1)

\frac{d}{d x} (ln (1 + x^{2}))

\int \frac{1}{10 x ^{6}} d x

f (x) = x x + 1

What is the derivative of 4x^3-26x^2+40x ?
The derivative of 4x^3-26x^2+40x is 12x^2-52x+40
What is the first derivative of 4x^3-26x^2+40x ?
The first derivative of 4x^3-26x^2+40x is 12x^2-52x+40