What is the derivative of x^2-2x-8 ?

The derivative of x^2-2x-8 is 2x-2

What is the first derivative of x^2-2x-8 ?

The first derivative of x^2-2x-8 is 2x-2

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\frac{d}{d x} (x^{2} - 2 x - 8)

2 x - 2

Solution steps

\frac{d}{d x} (x^{2} - 2 x - 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (2 x) - \frac{d}{d x} (8)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (8) = 0

= 2 x - 2 - 0

Simplify

= 2 x - 2

x y^{^{'}} + y = 9 x y^{2}, y (1) = 2

x^{3} - 6 x, - 2 x

x^{2} - 6 x, - x^{2} + 6

f (x) = 2 x^{2} - 4 x + 3

y^{^{''}} + y^{^{'}} + y = 1 + t + t^{2}

What is the derivative of x^2-2x-8 ?
The derivative of x^2-2x-8 is 2x-2
What is the first derivative of x^2-2x-8 ?
The first derivative of x^2-2x-8 is 2x-2