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Popular >

y^{''}+(1/x)y^'=0

Solution

y^{^{''}} + (\frac{1}{x}) y^{^{'}} = 0

Solution

y = c_{1} + c_{2} ln (x)

Solution steps

y^{''} (x) + (\frac{1}{x}) y^{'} (x) = 0

Solve linear ODE:

y = c_{1} + c_{2} ln (x)

y = c_{1} + c_{2} ln (x)

Graph

Popular Examples

integral of 4e^2

\int 4 e^{2} d x

y^'=(-(xy+1))/(xy+1)

y^{^{'}} = \frac{- ( x y + 1 )}{x y + 1}

y^'=(x-3)(y+1)^{2/3}

y^{^{'}} = (x - 3) (y + 1)^{\frac{2}{3}}

integral from 0 to pi/2 of-8sin^2(3x)

\int_{0}^{\frac{π}{2}} - 8 sin^{2} (3 x) d x

(dy)/(dx)=cos(x)

\frac{d y}{d x} = cos (x)

Frequently Asked Questions (FAQ)

What is the solution for y^{''}+(1/x)y^'=0 ?
The solution for y^{''}+(1/x)y^'=0 is y=c_{1}+c_{2}ln(x)