What is the derivative of (2x^2-4x^2) ?

The derivative of (2x^2-4x^2) is 2(2x^2-4x)(4x-4)

What is the first derivative of (2x^2-4x^2) ?

The first derivative of (2x^2-4x^2) is 2(2x^2-4x)(4x-4)

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\frac{d}{d x} ((2 x^{2} - 4 x)^{2})

2 (2 x^{2} - 4 x) (4 x - 4)

Solution steps

\frac{d}{d x} ((2 x^{2} - 4 x)^{2})

Apply the chain rule:

2 (2 x^{2} - 4 x) \frac{d}{d x} (2 x^{2} - 4 x)

= 2 (2 x^{2} - 4 x) \frac{d}{d x} (2 x^{2} - 4 x)

\frac{d}{d x} (2 x^{2} - 4 x) = 4 x - 4

= 2 (2 x^{2} - 4 x) (4 x - 4)

\frac{3}{s s ^{2} + 8 ss + 18 s}

\frac{d}{d x} (4 x - 3 x^{2} - y^{2} - (z - 1)^{2})

\frac{3}{x} - e^{4}

\frac{d}{d x} (- 5 x (2 x - 3)^{4})

\frac{\partial}{\partial v} (u (v, w) + v \cdot e^{w})

What is the derivative of (2x^2-4x^2) ?
The derivative of (2x^2-4x^2) is 2(2x^2-4x)(4x-4)
What is the first derivative of (2x^2-4x^2) ?
The first derivative of (2x^2-4x^2) is 2(2x^2-4x)(4x-4)