What is (\partial)/(\partial y)(2xy^2+x/(y^2)) ?

The answer to (\partial)/(\partial y)(2xy^2+x/(y^2)) is 4xy-(2x)/(y^3)

Popular >

(\partial)/(\partial y)(2xy^2+x/(y^2))

\frac{\partial}{\partial y} (2 x y^{2} + \frac{x}{y ^{2}})

4 x y - \frac{2 x}{y ^{3}}

Solution steps

\frac{\partial}{\partial y} (2 x y^{2} + \frac{x}{y ^{2}})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x y^{2}) + \frac{\partial}{\partial y} (\frac{x}{y ^{2}})

\frac{\partial}{\partial y} (2 x y^{2}) = 4 x y

\frac{\partial}{\partial y} (\frac{x}{y ^{2}}) = - \frac{2 x}{y ^{3}}

= 4 x y - \frac{2 x}{y ^{3}}

\frac{d}{d x} (ln (5^{x}))

\frac{\partial}{\partial x} (\frac{- 4}{x + y})

y = \frac{1}{7 x ^{\frac{6}{7}}}

x \to 0 lim (\frac{6 x}{sin ( x )})

f (x) = x^{2} - 7, (4, 9)

What is (\partial)/(\partial y)(2xy^2+x/(y^2)) ?
The answer to (\partial)/(\partial y)(2xy^2+x/(y^2)) is 4xy-(2x)/(y^3)