What is the tangent of f(x)=x^2-7,(4,9) ?

The tangent of f(x)=x^2-7,(4,9) is y=8x-23

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tangent of f(x)=x^2-7,(4,9)

tangent of

f (x) = x^{2} - 7, (4, 9)

y = 8 x - 23

Solution steps

Find the slope of

f (x) = x^{2} - 7 : \frac{df ( x )}{d x} = 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 8

Find the line with slope m=

8

and passing through

(4, 9) : y = 8 x - 23

y = 8 x - 23

\frac{( s + 1 )}{( s ^{2} + 4 s + 20 )}

x \to - \infty lim (\frac{4 + 5 e ^{4 x}}{5 - 6 e ^{5 x}})

\int - 2 x 1 - x^{2} d x

\frac{d}{d x} y - \frac{1}{cos ( x )} = 0

f (x) = ln (x + 1 + x^{2})

What is the tangent of f(x)=x^2-7,(4,9) ?
The tangent of f(x)=x^2-7,(4,9) is y=8x-23