What is the solution for derivative of y-1/(cos(x))=0 ?

The solution for derivative of y-1/(cos(x))=0 is y=ln(tan(x)+sec(x))+c_{1}

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derivative of y-1/(cos(x))=0

\frac{d}{d x} y - \frac{1}{cos ( x )} = 0

y = ln (tan (x) + sec (x)) + c_{1}

Solution steps

\frac{d y}{d x} - \frac{1}{cos ( x )} = 0

Isolate

y^{'} (x) : y^{'} (x) = \frac{1}{cos ( x )}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int \frac{1}{cos ( x )} d x

\int \frac{1}{cos ( x )} d x = ln (tan (x) + sec (x)) + c_{1}

y = ln (tan (x) + sec (x)) + c_{1}

f (x) = ln (x + 1 + x^{2})

x \to 8 - lim (\frac{4}{x - 8})

f (x) = - \frac{1}{2 x ^{2}}

\int e^{x} (cos (x) + sin (x)) d x

k = 2 \sum \infty \frac{3}{9 ^{k - 1}}

What is the solution for derivative of y-1/(cos(x))=0 ?
The solution for derivative of y-1/(cos(x))=0 is y=ln(tan(x)+sec(x))+c_{1}