What is the slope ofintercept (3,-2),(-5,0) ?

The slope ofintercept (3,-2),(-5,0) is y=-1/4 x-5/4

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slope ofintercept (3,-2),(-5,0)

slope intercept

(3, - 2), (- 5, 0)

y = - \frac{1}{4} x - \frac{5}{4}

Solution steps

Compute the slope

(3, - 2), (- 5, 0) : m = - \frac{1}{4}

Compute the

y

intercept:

b = - \frac{5}{4}

Construct the line equation

y = mx + b

where

m = - \frac{1}{4}

and

b = - \frac{5}{4}

y = - \frac{1}{4} x - \frac{5}{4}

x \to 0 lim (x \cdot 3^{\frac{1}{x}})

f (x) = tan^{5} (x)

\int \frac{( x ^{2} - 2 x + 1 )}{x ^{2} + x} d x

\frac{d}{d x} ((e^{- x} - e^{2}) (e^{x} + e^{- 5}))

\frac{\partial}{\partial x} (y - \frac{8}{x ^{2}})

What is the slope ofintercept (3,-2),(-5,0) ?
The slope ofintercept (3,-2),(-5,0) is y=-1/4 x-5/4