What is the solution for ydx+(y-x)dy=0 ?

The solution for ydx+(y-x)dy=0 is y=-x/(\W(-\frac{x){c_{1}})}

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ydx+(y-x)dy=0

y d x + (y - x) d y = 0

y = - \frac{x}{W ( - \frac{x}{c _{1}} )}

Solution steps

y d x + (y - x) d y = 0

Solve using substitution:

y = - \frac{x}{W ( - \frac{x}{c _{1}} )}

y = - \frac{x}{W ( - \frac{x}{c _{1}} )}

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What is the solution for ydx+(y-x)dy=0 ?
The solution for ydx+(y-x)dy=0 is y=-x/(\W(-\frac{x){c_{1}})}