What is the derivative of f(x)=ln(x+2) ?

The derivative of f(x)=ln(x+2) is 1/(x+2)

What is the first derivative of f(x)=ln(x+2) ?

The first derivative of f(x)=ln(x+2) is 1/(x+2)

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derivative of

f (x) = ln (x + 2)

\frac{1}{x + 2}

Solution steps

\frac{d}{d x} (ln (x + 2))

Apply the chain rule:

\frac{1}{x + 2} \frac{d}{d x} (x + 2)

= \frac{1}{x + 2} \frac{d}{d x} (x + 2)

\frac{d}{d x} (x + 2) = 1

= \frac{1}{x + 2} \cdot 1

Simplify

= \frac{1}{x + 2}

\frac{d}{d x} (sin (\frac{5 x - 3 x ^{3}}{x + 1}))

x^{n}

\int \frac{3 x ^{2} + x + 1}{x ^{2} - 2 x + 5} d x

arctan (\frac{2}{x})

x^{2} y^{^{''}} + y^{^{'}} = 0

What is the derivative of f(x)=ln(x+2) ?
The derivative of f(x)=ln(x+2) is 1/(x+2)
What is the first derivative of f(x)=ln(x+2) ?
The first derivative of f(x)=ln(x+2) is 1/(x+2)