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Popular >

(t+1)dt-1/(y^2)dy=0

Solution

(t + 1) d t - \frac{1}{y ^{2}} d y = 0

Solution

y = \frac{2}{- t ^{2} - 2 t + c _{1}}

Solution steps

(t + 1) d t - \frac{1}{y ^{2}} d y = 0

Solve separable ODE:

y = \frac{2}{- t ^{2} - 2 t + c _{1}}

y = \frac{2}{- t ^{2} - 2 t + c _{1}}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for (t+1)dt-1/(y^2)dy=0 ?
The solution for (t+1)dt-1/(y^2)dy=0 is y= 2/(-t^2-2t+c_{1)}