What is (\partial)/(\partial x)(6xy-2y^2) ?

The answer to (\partial)/(\partial x)(6xy-2y^2) is 6y

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(\partial)/(\partial x)(6xy-2y^2)

\frac{\partial}{\partial x} (6 x y - 2 y^{2})

6 y

Solution steps

\frac{\partial}{\partial x} (6 x y - 2 y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (6 x y) - \frac{\partial}{\partial x} (2 y^{2})

\frac{\partial}{\partial x} (6 x y) = 6 y

\frac{\partial}{\partial x} (2 y^{2}) = 0

= 6 y - 0

Simplify

= 6 y

\frac{d}{d x} (\frac{4}{7 x ^{2}})

\int \frac{x + 7}{x ^{2} + 3 x + 2} d x

y = \frac{1}{x - 2}

\frac{d y}{d x}, e^{(9 x y)} = 10 x

\int \frac{1}{2} cos (2 x) d x

What is (\partial)/(\partial x)(6xy-2y^2) ?
The answer to (\partial)/(\partial x)(6xy-2y^2) is 6y