What is the derivative of y= 1/(x-2) ?

The derivative of y= 1/(x-2) is -1/((x-2)^2)

What is the first derivative of y= 1/(x-2) ?

The first derivative of y= 1/(x-2) is -1/((x-2)^2)

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derivative of

y = \frac{1}{x - 2}

- \frac{1}{( x - 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{x - 2})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((x - 2)^{- 1})

Apply the chain rule:

- \frac{1}{( x - 2 ) ^{2}} \frac{d}{d x} (x - 2)

= - \frac{1}{( x - 2 ) ^{2}} \frac{d}{d x} (x - 2)

\frac{d}{d x} (x - 2) = 1

= - \frac{1}{( x - 2 ) ^{2}} \cdot 1

Simplify

= - \frac{1}{( x - 2 ) ^{2}}

\frac{d y}{d x}, e^{(9 x y)} = 10 x

\int \frac{1}{2} cos (2 x) d x

e^{y} \frac{d y}{d x} = 2 x

\int 20 y d y

\frac{d}{d x} (ln (arcsin (2 x)))

What is the derivative of y= 1/(x-2) ?
The derivative of y= 1/(x-2) is -1/((x-2)^2)
What is the first derivative of y= 1/(x-2) ?
The first derivative of y= 1/(x-2) is -1/((x-2)^2)