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Popular >

y^'=6+t-y

Solution

y^{^{'}} = 6 + t - y

Solution

y = t + 5 + \frac{c _{1}}{e ^{t}}

Solution steps

y^{'} (t) = 6 + t - y

Solve linear ODE:

y = t + 5 + \frac{c _{1}}{e ^{t}}

y = t + 5 + \frac{c _{1}}{e ^{t}}

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Frequently Asked Questions (FAQ)

What is the solution for y^'=6+t-y ?
The solution for y^'=6+t-y is y=t+5+(c_{1})/(e^t)